R12 Commutator Factorization No-Go
Status: rejected as an R12 invention. Observable event commutators can recover a conditional central/direct product of transition groups, but do not identify a product residual state. Complete positive cases reduce to known group, automata, trace-monoid, or Cartesian-graph decomposition.
1. Observable commutator support
Let X be N finite residual states, A be m labeled events with
permutation transitions T_a, and let joint late-query signatures separate
states. Define
S(a,b) = {x in X : T_a T_b x != T_b T_a x}.
Separating queries make S(a,b) experimentally observable when states can be
prepared reproducibly. State-uniform event independence means S(a,b) is
empty.
2. Commutator-to-central-product theorem
Let G=<T_a:a in A>. Connect event labels that do not commute and let the
connected components be A_1,...,A_k, with
G_i = <T_a : a in A_i>.
Then the G_i commute pairwise and multiplication gives a surjection
mu : product_i G_i -> G.
Every coordinate of ker(mu) lies in
G_i intersect <G_j:j!=i> subset Z(G_i).
Commutators therefore identify at most a central product. The group is the
direct product of the G_i exactly when all cross-intersections are trivial;
centerless factors are sufficient.
This algebraic condition still does not factor the state.
3. Stabilizer obstruction
Assume the action is transitive and fix state x. Let
H = stabilizer_G(x),
H_i = H intersect G_i.
Even when G is a direct product, a factorwise state decomposition
X isomorphic to product_i G_i/H_i
exists iff
H = product_i H_i,
equivalently |Gx|=product_i |G_i x|. A diagonal or subdirect stabilizer
couples the apparent modules.
The smallest useful counterexamples are:
- on
Z_3,a(x)=x+1andb(x)=x-1commute but generate the sameC_3, not two modules; S_3 x S_3acts faithfully on six statesX=S_3by(g,h).x=g x h^-1; its factors commute and form a true direct product, but the stabilizer is diagonalS_3, so6 != 6*6and no product state exists;- the regular
C_2 x C_2action has three inequivalent choices of twoC_2factors, so abelian centralizers do not select one decomposition.
4. Probe and information cost
With reproducible access to every state, recovering all event tables costs
mNq readouts for q separating query bits. Directly testing every pair costs
2 binomial(m,2) N q
readouts. Independent bit noise eta<1/2 adds the repetition factor
O((1-2eta)^-2 log(Pq/delta)).
Without full-support state preparation or a positive minimum state
probability, no finite exact guarantee exists. An adversary can change one
unobserved state-event transition and destroy commutation or factorization.
Thus unrestricted state-uniform locality needs Omega(mN) transition probes.
If a product chart and event assignment are already known, local tables use
sum_i m_i n_i log n_i
bits instead of mN log N, for N=product_i n_i. But an opaque chart can cost
log(N!)=Theta(N log N) bits and exact discovery already pays the extensional
probe cost. Retained state does not shrink:
sum_i log n_i = log N.
Query savings additionally require low-arity factorized readouts.
5. Prior-art collapse
- finite machine decomposition is covered more generally by Krohn-Rhodes cascade/wreath products;
- direct-product decomposition of permutation groups is polynomial-time from generators (Wilson);
- Cartesian transition-graph factorization and permutation-automata decomposition are established algorithms;
- trace monoids encode commuting event words but do not prove separate storage coordinates;
- subdirect and diagonal couplings are the standard Goursat obstruction.
A structure-aware group, automata, graph-factorization, or message-passing control receives the same conditional resource gain.
6. Verdict
No CPU experiment is authorized. A survivor must expose an ordinary-trace invariant that defeats central and subdirect coupling, identifies modules from sub-extensional coverage, and yields a resource advantage over established decomposition algorithms. Pairwise commutators do not.